Math, asked by shaileshpathakbargao, 8 months ago

A park is 25- m long and 20- which is 22 m wide, what would be the inside perimeter of the walkway? m wide. Find its perimeter. If a walkway is to be constructed inside the park 3​

Answers

Answered by Anonymous
2

Step-by-step explanation:

Given : a park is 25 4/5 m long and 20 2/3 m wide . a walkway is to be constructed inside the park which is 2 3/8m wide,

To find : perimeter of park

inside perimeter of the walkway

Solution:

Park length 25 4/5 m = 25 + 4/5 m = (125 + 4)/5 = 129/5 m

Park Width = 20 2/3 m = 20 + 2/3 m = (60 + 2)/3 = 62/3 m

Park perimeter = 2 ( Length + Width )

= 2 ( 129/5 + 62/3)

= 2( 387 + 310)/15

= 2(697)/15

= 1394 / 15

= 92 14/15 m

walkway is to be constructed inside the park which is 2 3/8m wide

2 + 3/8 m = 19/8 Meter

8 times the width will be reduced

8 * 19/8 = 19 m

inside perimeter of the walkway = 92 14/15 - 19

= 75 14/15 m

Park perimeter = 92 14/15 m

inside perimeter of the walkway = 75 14/15 m

Answered by amritamohanty918
1

Answer:

75 14/15 m is your answer

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