A park is 25 upon 4/5m long and 20 upon 2/3m wide. Find its perimeter. If a walkway is to be constructed inside the park which is 2 upon 3/8m wide ,what would be the inside perimeter of the walkway
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Answer:
park perimeter= 2(length+width)
= 2(129/5+62/3)
=2(387+310)/15
= 2(697)/15
=13 94/15
= 92 14/15mitre
walk way is to be constructed inside the park which is 2 3/8 m wide
2+3/8m= 19/8 m
8times the width will be reduced
8*19/8=19m
inside perimeter of the walkway = 92
14/15-19
75 14/15metre ans.....
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