Question

A park is 60 M long and 40m broad in the middle of the park there is a circular tank of radius 7m find the area of the park the area of circular tank the circumference of the circular tank the cost of turfing the remaining portion of the park at the rate of Rs 2.50 square

Answer 1

area of the park=60m X 40m=2400 sq. m
area of circular tank=
$\pi {r}^{2} \\ = \frac{22}{7} \times 7 \times 7 \\ = 22 \times 7 = 154 {m}^{2}$
remaining portion=area of park-area of circular tank
=(2400-154) sq. m=2246 sq. m

cost of turfing=Rs 2.5 X 2246=Rs 5615

Answer 2

L = 60m , B= 40m

Area of the park = 60×40 = 2400 sq m

Radius of tank = r = 7m

∴Area of circular tank = $\pi$ $r^{2}$ = 22/7×7×7 = 154 sq m

Circumference of tank = 2 $\pi$ r = 2×22/7×7=44m

Area of remaining portion = area of park - Area of tank

                                           = 60×40 - 154 = 2246 sq m

Cost per sqm = Rs 2.50

∴ Cost of turfing the remaining portion = 2.50×2246 = Rs 5615