A park is in the shape of a quadrilateral ABCD in which AB = 9 m, BC = 12 m, CD = 5 m and AD = 8 m. If Angle C =90degree , find the area of the park
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Step-by-step explanation:
area of the triangle ABC
=1/2 base ×height
=1/2×12×15cm2
=90cm2
semiperimeter of the triangle 12+9+15/2
=36/2cm=18 cm
now by heron's formula
Area of the ∆ACD= √18(18-12)(18-9)(18-15) (unriot all)
√18×6×9×3
=√3×6×6×3×3×3
3×3×6
=54
so the area of park =90+54cm2
= 144cm2
I hope it helps you
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Answer:
The principle of reversibility presupposes that the attenuation of a light ray during its passage through an optical medium because of reflection, refraction, and absorption is not affected by a reversal of the direction of the ray.
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