A park is of the shape of a circle of diameter 7 m. It is surrounded by a path of width of 0.7 m. Find the expenditure of cementing the path, if its cost is Rs 110 per sq. m.
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Answered by
27
Radius(r) of inner circle=7/2=3.5m
Radius (R)of outer circle=3.5+0.7=4.2m
Area of path =Area of inner circle -Area of outer circle
=πR2-πr2
=π( {4.2}2-{3.5}2)
=π(5.39)
=16.94 m2
cost of cementing=16.94*110
= Rs. 1863.4
I hope this will help you
if not then comment me
Radius (R)of outer circle=3.5+0.7=4.2m
Area of path =Area of inner circle -Area of outer circle
=πR2-πr2
=π( {4.2}2-{3.5}2)
=π(5.39)
=16.94 m2
cost of cementing=16.94*110
= Rs. 1863.4
I hope this will help you
if not then comment me
Answered by
5
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