A park is of the shape of circle of diameter 7 m .It is surrounded by a path of width of 0.7 m . Find the expenditure of cementing the path, if its cost is rupees 110 per sq. m.
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area of the park=diameter of circle * 22/7m^2
7*22/7m^2
22m^2
diameter including the width=7+0.7 m
7.7m
area of that circle=7.7*22/7
24.2m^2
area of the path=area of path&circle-area of circle
(24.2-22)m^2
2.2m^2
rate of expenditure=rs 110/m^2
cost of cementing it=rs 110*2.2
rs 242
7*22/7m^2
22m^2
diameter including the width=7+0.7 m
7.7m
area of that circle=7.7*22/7
24.2m^2
area of the path=area of path&circle-area of circle
(24.2-22)m^2
2.2m^2
rate of expenditure=rs 110/m^2
cost of cementing it=rs 110*2.2
rs 242
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