Question

A park of length 50 m amd brradth 30m needs to be enclosed with a wire fence.If the fencing wire costs ₹120 per metre,find the cost of enclosing of ths park.please explain it​

Answer 1

Correct Question-:

• A park of length 50 m amd breath 30m needs to be enclosed with a wire fence. If the fencing wire costs ₹120 per metre,find the cost of enclosing of ths park .

AnswEr-:

• $\boxed{\purple{\sf{The\:rate\:of\:fencing \:the\:boundary \:of\:Park \:= \: ₹19,200 }}}$

Explanation-:

Given-:

• The length of park is 50 m .
• The breadth of park is 30 m .
• The rate of fencing the park with wire is ₹120 per metre .

☆ Figure related to question -:

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To Find -:

• The rate of Fencing the park .

Analysis,

• As we know the area which is need to fence or the area which is need to be enclosed with wire is the boundary of park and boundary of the park is equal to the perimeter of the park .

Now ,

$\boxed{\purple{\sf{Perimeter \: of\:Rectangle\: = \: 2(length + Breadth)}}}$

Here ,

• Length of park = 50 m .
• Breath of park = 30 m .

• $\implies {\pink{\sf{ Perimeter \: = 2(50+30)}}}$
• $\implies {\pink{\sf{ Perimeter \: = 2(80)}}}$
• $\implies {\pink{\sf{ Perimeter \: = 160m }}}$

Therefore,

• $\boxed{\purple{\sf{Perimeter \:of\:Park \:= \: 160m }}}$

As ,we know that ,

• The rate of fencing the park with wire is ₹120 per metre.

Then ,

• The rate of fencing the boundary of park with wire -: Perimeter of park × The rate of fencing per metres.

Here ,

• The rate of fencing the park with wire is ₹120 per metre.
• Perimeter of park is 160 m .

Now ,

• $\implies {\pink{\sf{ Rate \:of\:Fencing = 120 × 160}}}$
• $\implies {\pink{\sf{ Rate \:of\:Fencing = ₹19,200}}}$

Hence ,

• $\boxed{\purple{\sf{The\:rate\:of\:fencing \:the\:boundary \:of\:Park \:= \: ₹19,200 }}}$

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♤ More to know ♤

♡ Formulas related to Rectangle-:

• Perimeter of a Rectangle Formula -: Perimeter = 2 (length + breadth)
• Area of a Rectangle Formula -: Area = length × breadth
• Diagonal of a Rectangle Formula -: Diagonal = √length ² + breadth ²

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