Question

a park shaped like a rectangle has a length of 24 meters and width of 18 meters if trees are plated on its sides with gaps of 2 meters between them,how many trees are needed ?

Answer 1

Answer:

perimeter of the park=2(l+b)

=2(24+18)m

=2×42m=84m

no. of trees=84/2=42Ans

Answer 2

Given,

The shape of the park is in the form of a rectangle.

The length of the park= 24m

The width of the park= 18m

The distance that separates two trees= 2m

To Find,

The total number of trees needed to plant along the perimeter of the park.

Solution,

The perimeter of the park = $2(l+b)$

where $l$ is the length and,

           $b$ is the breadth.

On substitution,

Perimeter = $2(24+18)$

⇒ $2(42)$

⇒ 84

Thus, the total perimeter of the park is 84m.

Trees are planted at a distance of 2m apart from each other.

∴The number of trees needed to cover 84 m = $\frac{84}{2}$

⇒ 42.

Henceforth, the total number of trees needed to cover the perimeter of the park is 42.