A parrot flying at a height of 300 m above sea level with a force of 10 n work done is?
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Class 10
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>>Some Applications of Trigonometry
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>>An aeroplane is flying at a...
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An aeroplane is flying at a height of 300 m above the ground. Flying at this height, the angles of depression from the aeroplane of two points on both banks of a river in opposite directions are 45
o
and 60
o
respectively. Find width of the river. [Use
3
=1.732]
Medium
Solution
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Let A be the aeroplane BD is the length of the river
tan45
o
=
BC
AC
1=
BC
300
BC=300m
tan60
o
=
CD
AC
3
=
CD
300
CD=
3
300
×
3
3
=
3
300
3
=100
3
=1.732×100=173.2
width of river =BC+CD=300+173.2=473.2m
Answer:
Displacement is along the height 300m above sea level (horizontal line)
Force is applied inthe downward direction (to push the air down to fly)
Thus,Theta is 90°
W=F S Cos theta
W=10S0
W=0