Math, asked by NikkoArmy, 1 month ago

a part of 1m wide runs around and inside a Square Garden of side of 20m. the cost of levelling the path at the rate of ₹2.25 per square metre is

Given options:
₹154
₹164
₹182
₹171

[need solution]
(^_^)​

Answers

Answered by Itzchiyuu
19

Answer:

Let ABCD, the square garden of side= 30 m.

Let ABCD, the square garden of side= 30 m.PQRS is the region inside the garden.

Let ABCD, the square garden of side= 30 m.PQRS is the region inside the garden.so,

Let ABCD, the square garden of side= 30 m.PQRS is the region inside the garden.so,PQ = (30 -1-1 ) = 28 m

Let ABCD, the square garden of side= 30 m.PQRS is the region inside the garden.so,PQ = (30 -1-1 ) = 28 malso

Let ABCD, the square garden of side= 30 m.PQRS is the region inside the garden.so,PQ = (30 -1-1 ) = 28 malsoPS = ( 30 – 1 – 1 ) = 28 m

Let ABCD, the square garden of side= 30 m.PQRS is the region inside the garden.so,PQ = (30 -1-1 ) = 28 malsoPS = ( 30 – 1 – 1 ) = 28 m (i) Area of the path = Area of ABCD – Area of PQRS

Let ABCD, the square garden of side= 30 m.PQRS is the region inside the garden.so,PQ = (30 -1-1 ) = 28 malsoPS = ( 30 – 1 – 1 ) = 28 m (i) Area of the path = Area of ABCD – Area of PQRS = [( 30 x 30) – (28 x 28)]

Let ABCD, the square garden of side= 30 m.PQRS is the region inside the garden.so,PQ = (30 -1-1 ) = 28 malsoPS = ( 30 – 1 – 1 ) = 28 m (i) Area of the path = Area of ABCD – Area of PQRS = [( 30 x 30) – (28 x 28)]= 900 – 784

Let ABCD, the square garden of side= 30 m.PQRS is the region inside the garden.so,PQ = (30 -1-1 ) = 28 malsoPS = ( 30 – 1 – 1 ) = 28 m (i) Area of the path = Area of ABCD – Area of PQRS = [( 30 x 30) – (28 x 28)]= 900 – 784 = 116 sq.m

Let ABCD, the square garden of side= 30 m.PQRS is the region inside the garden.so,PQ = (30 -1-1 ) = 28 malsoPS = ( 30 – 1 – 1 ) = 28 m (i) Area of the path = Area of ABCD – Area of PQRS = [( 30 x 30) – (28 x 28)]= 900 – 784 = 116 sq.m (ii) Area of the remaining portion in which the grass is planted = Area of square PQRS

Let ABCD, the square garden of side= 30 m.PQRS is the region inside the garden.so,PQ = (30 -1-1 ) = 28 malsoPS = ( 30 – 1 – 1 ) = 28 m (i) Area of the path = Area of ABCD – Area of PQRS = [( 30 x 30) – (28 x 28)]= 900 – 784 = 116 sq.m (ii) Area of the remaining portion in which the grass is planted = Area of square PQRS = 28 x 28

Let ABCD, the square garden of side= 30 m.PQRS is the region inside the garden.so,PQ = (30 -1-1 ) = 28 malsoPS = ( 30 – 1 – 1 ) = 28 m (i) Area of the path = Area of ABCD – Area of PQRS = [( 30 x 30) – (28 x 28)]= 900 – 784 = 116 sq.m (ii) Area of the remaining portion in which the grass is planted = Area of square PQRS = 28 x 28 = 784 sq.m

Let ABCD, the square garden of side= 30 m.PQRS is the region inside the garden.so,PQ = (30 -1-1 ) = 28 malsoPS = ( 30 – 1 – 1 ) = 28 m (i) Area of the path = Area of ABCD – Area of PQRS = [( 30 x 30) – (28 x 28)]= 900 – 784 = 116 sq.m (ii) Area of the remaining portion in which the grass is planted = Area of square PQRS = 28 x 28 = 784 sq.m cost of planting the grass in the region PQRS = area x cost = 764 x 40

Let ABCD, the square garden of side= 30 m.PQRS is the region inside the garden.so,PQ = (30 -1-1 ) = 28 malsoPS = ( 30 – 1 – 1 ) = 28 m (i) Area of the path = Area of ABCD – Area of PQRS = [( 30 x 30) – (28 x 28)]= 900 – 784 = 116 sq.m (ii) Area of the remaining portion in which the grass is planted = Area of square PQRS = 28 x 28 = 784 sq.m cost of planting the grass in the region PQRS = area x cost = 764 x 40 =31,360

Hope it will helpful for you thanks...

Borahae....

Answered by xXItzUrMajnu01Xx
3

Answer:

option D( Rs. 171) is correct

The cost of levelling the park at the rate of rupees 2.25 per square metre is Rs.171

Step-by-step explanation:

Side of square garden = 20 m

The path of one metre wide runs around and inside a Square Garden of side 20 metre

So, Inner length = 20-(1+1)=18 m

Area of square = (side) ^2

Area of Path = Outer Area - Inner area

Area of Path =20^2 -- 18^2

Area of Path = 76 m^2

Cost of leveling 1 sq.m. = 2.25

Cost of leveling 76 sq.m. = 2.25 \times 76 = Rs.171

Hence The cost of levelling the park at the rate of rupees 2.25 per square metre is Rs.171

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