Physics, asked by mk004nadhav, 6 hours ago

a part of a larger circuit is shown in the figure. both batteries shown have resistance 1 ohm each. if points A and B are equipotential and a current of 2A flows from A towards B, then EMF E in volts is :​

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Answered by pinkusolanki21
0

Answer:

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V=6V

R

1

=2ohms

R

2

=3ohms

(a) Resistors are connected in parallel.

(b) p.d. across each resistor is same and is equal to 6V.

(c) 2 ohms resistance have bigger share of current because of its lower resistance.

(d) Effective resistance = R

1/R=1/2+1/3

1/R=5/6

R=1.2ohms

(e) Current flowing through battery ,

I=

R

V

=

1.2

6

=5amps

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