a part of a larger circuit is shown in the figure. both batteries shown have resistance 1 ohm each. if points A and B are equipotential and a current of 2A flows from A towards B, then EMF E in volts is :
Attachments:
Answers
Answered by
0
Answer:
Verified by Toppr
V=6V
R
1
=2ohms
R
2
=3ohms
(a) Resistors are connected in parallel.
(b) p.d. across each resistor is same and is equal to 6V.
(c) 2 ohms resistance have bigger share of current because of its lower resistance.
(d) Effective resistance = R
1/R=1/2+1/3
1/R=5/6
R=1.2ohms
(e) Current flowing through battery ,
I=
R
V
=
1.2
6
=5amps
Similar questions