A part of circuit is shown in fig. If current is decreasing at rate of 0.3 A/sec. then, what will be potential difference (V_(A) - V_(B)) when the current becomes 2A?
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We will write voltage drop equation as we go from A to B.
V
A
−iR+V+L
dt
di
=V
B
V
A
−5×1+15−5×10
−3
×(−10
3
)=V
B
V
B
−V
A
=15
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