A part of monthly expenses of a family is constant and the remaining varies with the
price of rice. When the cost of rice is Rs.250 per quintal, the monthly expenditure of the
family is Rs.1000 and when the cost of rice is Rs.240 per quintal the monthly expenditure is
Rs.980. Find the monthly expenditure of the family when the cost of rice is Rs.300 per
quintal.
Answers
Answered by
5
Hi Nidra
Let the amount of wheat consumption of the family be x quintals and let the constant expenditure be y rupees.
So, formulating simultaneous equations based on the data given in the question:
250x + y = 1000 ---i)
240x + y = 980 ---ii)
Subtracting ii) from i), we get,
10x = 20
=> x = 2.
Putting x = 2 in equation i), we have
500 + y = 1000
=> y = 500.
Now, when the cost of wheat is Rs. 350,
we have the monthly expense as:
350 * 2 + 500 = 1200.
Thus, the montly expenditure is Rs. 1200.
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PLZ MARK IT AS THE BRAINLIEST ANSWER
Let the amount of wheat consumption of the family be x quintals and let the constant expenditure be y rupees.
So, formulating simultaneous equations based on the data given in the question:
250x + y = 1000 ---i)
240x + y = 980 ---ii)
Subtracting ii) from i), we get,
10x = 20
=> x = 2.
Putting x = 2 in equation i), we have
500 + y = 1000
=> y = 500.
Now, when the cost of wheat is Rs. 350,
we have the monthly expense as:
350 * 2 + 500 = 1200.
Thus, the montly expenditure is Rs. 1200.
© Ã K $ H Ã Y
HØPË ÏT HËLPZ
PLZ MARK IT AS THE BRAINLIEST ANSWER
AkShAyKrIzZ192:
Nidhra plz don't forget to mark it as BRAINLIEST answer
Answered by
23
★ PROFIT AND LOSS ★
Let the constant expenditure be ₹x
And, Let the consumption of rice by the family be y quintals.
Now,
And,
Subtracting (2) from (1) :
We get,
−
------------------------------------
So,
Now,
∴
Putting the value in (1),
We get,
⇒ [tex]x + 250(2) = 1000[/tex]
⇒
⇒
∴
Now, Total monthly expenditure when the cost of rice ₹300 = constant expenditure + consumption of rice at ₹ 300 per quintal.
→ From (3) and (4)
Hence, the Total monthly expenditure when the cost of rice ₹300 is ₹ 1200.
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