A part of monthly hostel charges is fixed and the remaining depends on the number of days one has taken food in tamil when a student a text for a food 20 days and has to pay rupees 1000 as hostel charges well as student be who takes food for 26 days payrupees 1180 at the hostel charges fees charged
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Answered by
12
let the fixed hostel charges be x Rupee's
one day food charges be y Rupee's
A.T.Q.
x+20y= 1000 ...eq1
x+26y=1180 ...eq2
subtract both equations
-6y = -180
y=180/6=30 Rupee's
So,
x+20(30)=1000
x=1000-600
x=400 Rupee's
fixed charge of hostel is 400 Rupee's
one day food charges is 30 rupees.
Hope it helps you.
one day food charges be y Rupee's
A.T.Q.
x+20y= 1000 ...eq1
x+26y=1180 ...eq2
subtract both equations
-6y = -180
y=180/6=30 Rupee's
So,
x+20(30)=1000
x=1000-600
x=400 Rupee's
fixed charge of hostel is 400 Rupee's
one day food charges is 30 rupees.
Hope it helps you.
Answered by
1
let the hostel fixed charge be x rs.
and daily food charge be y rs per day
now ,
first condition , x +20y =1000
x = 1000 - 20 y -------- ( 1 )
also by second condition , x + 26 y = 1180
x = 1180 - 26 y. ------- ( 2 )
from 1 and 2 we get
1000 - 20y = 1180 - 26y
26 y - 20 y = 1180 - 1000
6y = 180
y = 30
putting this in eq 1
x = 1000 - 20 ×30
x = 1000 - 600
x = 400 rs
so fixed charge is 400 rs and daily charge is 30 rs
and daily food charge be y rs per day
now ,
first condition , x +20y =1000
x = 1000 - 20 y -------- ( 1 )
also by second condition , x + 26 y = 1180
x = 1180 - 26 y. ------- ( 2 )
from 1 and 2 we get
1000 - 20y = 1180 - 26y
26 y - 20 y = 1180 - 1000
6y = 180
y = 30
putting this in eq 1
x = 1000 - 20 ×30
x = 1000 - 600
x = 400 rs
so fixed charge is 400 rs and daily charge is 30 rs
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