Question

-A part of rs 60,000 was invested at 12% p.a, for 5 years and the
rest was invested at 10% p.a. for 4 years. If the total interest
earned was Rs 27,000 find the sum of money invested at each rate.

Answer 1

Answer:

X= 15000 , y=45000, x+y = 60000

Step-by-step explanation:

let x+y =60000

but given

x*( 12/100)*5+y*(10/100)*4=27000

3x/5+2x/5 =27000

3x+2y=135000

x+2(x+y)=135000

x+120000=135000

x=15000

y=45000

Answer 2

15000 at 12% and 45000 at 10%

Step-by-step explanation:

Consider x be the first part of the investment,

Principal, P = x,

Rate of interest, r = 12%,

Time, t = 5 years,

So, the interest,

$I_1=\frac{P\times r\times t}{100}$

$=\frac{x\times 12\times 5}{100}$

$=\frac{60x}{100}$

$=\frac{3x}{5}$

Now consider the second part of the investment is y,

P = y, r = 10%, t = 4 years,

Then interest,

$I_2=\frac{y\times 10\times 4}{100}$

$=\frac{40y}{100}$

$=\frac{2y}{5}$

According to the question,

$I_1+I_2=27000$

$\frac{3x}{5}+\frac{2y}{5}=27000$

$3x+2y = 135000$   ............(1)

Also, total investment = 60,000

⇒ x + y = 60,000               ............(2),

Equation (1) - 3 × equation (2),

-y = 135000 - 180000

y = 45,000

From equation (2),

x + 45000 = 60,000

⇒ x = 15000

Hence, investment at 12% is rs 15,000 and at 10% is 45,000

#Learn more:

A certain sum of money invested for 5 years at 8% p.a. simple interest earns a simple interest of rs 12000. find the sum of the money and the compound interest earned

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