Question

a part of Rs 60000 was invested at 12% p.a. for 5 years and the rest was invested at 10% p.a. for 4 years l. if the total interest earned was Rs 27000, find the sum of money invested at each rate. ​

Answer 1

Answer:

X= 15000 , y=45000, x+y = 60000

Step-by-step explanation:

let x+y =60000

but given

x*( 12/100)*5+y*(10/100)*4=27000

3x/5+2x/5 =27000

3x+2y=135000

x+2(x+y)=135000

x+120000=135000

x=15000

y=45000

Answer 2

Answer:

15000 at 12% and 45000 at 10%

Step-by-step explanation:

Consider x be the first part of the investment,

Principal, P = x,

Rate of interest, r = 12%,

Time, t = 5 years,

So, the interest,

Now consider the second part of the investment is y,

P = y, r = 10%, t = 4 years,

Then interest,

According to the question,

............(1)

Also, total investment = 60,000

⇒ x + y = 60,000 ............(2),

Equation (1) - 3 × equation (2),

-y = 135000 - 180000

y = 45,000

From equation (2),

x + 45000 = 60,000

⇒ x = 15000

Hence, investment at 12% is rs 15,000 and at 10% is 45,000

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