Question

A parth 3 m wide rules around the inside of a square Park of side 60m find the area of the path​

Answer 1

Step-by-step explanation:

Given ABCD is a park of  [side = 6m ]

now 

Portion outside (EFGH) is a running path of width = 3m

area of running path = area of ABCD - area of EFGH

length of side EFGH =60−6=54m

Then

area of running path =(60)2−(54)2

Area=3600−2916

Area=684m2

hope it will help u

mark me as brainlist

Answer 2

Step-by-step explanation:

Side of the square park = 60m

Area of the square park without the path = S × S

= ( 60 × 60 ) m² = 3600 m²

Side of the square park with the path = ( 60 + 3) m = 63m

Therefore, Area of the square park with the path

= ( 63 × 63 ) m² = 3969 m²

Now , Area of the path = ( 3969 - 3600) m² = 369m²

please mark as brainliest