Question

A partial pressure of ethane over a solution conaining 6.5×10g of ethane is 1 bar if the solution contain 5.00×10g of ethane the what shall the partial pressene of the gass

Answer 1

According to Henry’s law

.m = k x p

Substituting the given values in the above equation.

We get

6.56 x10-3 = k x 1

Or

k = 6.56 x10-3

Now when m = 5 x 10-2,

Then again substituting the given values in Henry’s law equation,we get

 5 x 10-2 = 6.56 x10-3 x p

Or

p = 7.62 bar

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