Question

A partical is executing the motion x=5sin(ωt-θ).identify the value of maximum acceleration a)(5)^-1/2ω b)25ω c)5ω^2 d)ω/2

Answer 1

Answer:

Explanation:

differentiate  x to get velocity

dx/dt  =  5 cos (wt- Ф) (-w)

          = =    5w cos (wt - Ф)

again differentiate

$\frac{d^2x}{dt^2}$ = 5w {-sin(wt - Ф)} (w)

                                          = $5w^2$  {-sin(wt - Ф)}

maximum value   =  $5w^2$

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