Question

a partical is moving along a circular path of radius 16m and it completes one revolution in 30sec. If total time of motion is 75sec, the displacement of the partical is ___
1) 16m
2) 54m
3) 32m
4) 75m​

Answer 1

Given :-

• A partical is moving along a circular path of radius 16m.

• It completes one revolution in 30 second.

• Total time of motion is 75 seconds.

To Find :-

• The displacement of the particle.

Solution :-

• In 30 seconds, a particle completes one revolution.

So,

75 seconds can be break down as

• 75 seconds = 30 seconds + 30 seconds + 15 seconds

Thus,

• In 75 seconds, a particle takes 2 complete revolution and one half revolution.

As we know that,

• Displacement is the shortest distance between the initial and final position.

Thus,

• Displacement, PQ = Diameter = 2 × radius = 32 m.

$\overbrace{ \underline { \boxed { \rm \therefore \: The \: displacement \: of \: particle \: is \: 32 \: m)}}}$

$\boxed{ \sf \: Option \: (3) \: is \: correct}$

Additional Information :-

• Displacement is the shortest distance between the initial and final position.

• It is a vector quantity i.e. it has both magnitude and direction.