Physics, asked by hardikgaur688, 1 month ago

A partical is moving along a circular path with uniform speed then find out magnitude in change velocity when partical moves
Point A to B
Point A to c
Point A to D
Point A to A​

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Answers

Answered by iamXinsaan101
1

Correct option is

C

2vsin20

o

Let the velocity at point P

v

1

=v

i

^

So the velocity at point Q will be

v

2

=vcos40

0

i

^

−vsin40

0

j

^

Change in velocity

Δv

=

v

2

v

1

=(vcos40

0

i

^

−vsin40

0

j

^

)−v

i

^

Magnitude of change of velocity

∣Δv∣=

(vcos40

0

−v)

2

+(−vsin40

0

)

2

On solving we get

∣Δv∣=2vsin20

0

thanks (◍•ᴗ•◍)❤

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