A partical is moving along a circular path with uniform speed then find out magnitude in change velocity when partical moves
Point A to B
Point A to c
Point A to D
Point A to A
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Correct option is
C
2vsin20
o
Let the velocity at point P
v
1
=v
i
^
So the velocity at point Q will be
v
2
=vcos40
0
i
^
−vsin40
0
j
^
Change in velocity
Δv
=
v
2
−
v
1
=(vcos40
0
i
^
−vsin40
0
j
^
)−v
i
^
Magnitude of change of velocity
∣Δv∣=
(vcos40
0
−v)
2
+(−vsin40
0
)
2
On solving we get
∣Δv∣=2vsin20
0
thanks (◍•ᴗ•◍)❤
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