Question

A partical is projected with a velocity v, so that its range on a horizontal plane is twice the greatest height attained. if g is acceleration due to gravity then its range is

Answer 1

H = R tan Ф / 4

R = 2 H

So tan Ф = 2

sin 2Ф = 2 * 2 / (1+2²) = 0.8

range = v² sin 2Ф / g = 0.8 v²/g