Question

a partical move along circle of radius R and it's velocity depend on distance covered by as V=lemda√S.find angle between acceleration and velocity​

Answer 1

Answer:

From the equation v=a

s

A

t

=

dt

dv

=

2

s

a

dt

ds

=

2

s

a

a

s

=

2

a

2

, and

A

n

=

R

v

2

=

R

a

2

s

As A

t

is a positive constant, the speed of the particle increases with time, and the tangential acceleration vector and velocity vector coincides in direction.

Hence the angle between

v

and

A

is equal to that between

A

t

an

A

, and α can be found by means of the formula:

tanα=

∣A

t

∣

∣A

n

∣

=

2

a

2

R

a

2

s

=

R

2s