Physics, asked by parulranyal583, 1 year ago

A partical moves from position r1 vector =(3i+2j- 6k)m to position r2 vector (14i+3j+9k)m under the action of force ,F vector =(4i+j+3k)N . The work donee will be

Answers

Answered by Anonymous
5
r vector =r2-r1
=11i +j + 15k

Work =Fvector.r vector
=(4i+j+3k).(11i+j+15k)
=44+1+45
=90J
Answered by 4rajashekar4
1

Answer:

Explanation:

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