Question

A partical moves towards east with velocity 5 m/s. After 10 seconds it's direction changes towards north with same velocity.The average acceleration of the particle is?​

Answer 1

Intial velocity=v1=5m/seast wards

then after time t=10sec

v2=5m/s north wards

δv=

V

$\sqrt[1]{2}$

$+ v \sqrt[2]{2}$

$\sqrt[25]{ + 25} = 50$

acceleration

×

2

2

=

2

1

towards n-w

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