Question

A partical performs linear SHM of amplitude 5 cm. At what displacement from its mean position will the potential energy of the partical be 20% of its total energy ​

Answer 1

Answer:

Displacement =

$\sqrt{5}$

Explanation:

Total energy of a particle executing SHM is

$\frac{1}{2}ka {}^{2}$

20% of total energy = potential energy of the particle at that position.

20% ok 1/2ka^2 = 1/2kx^2