Question

A partical starts from the original at t=0s . with a velocity of ten.0 jcapm\s and moves plane with constant acceleration of (8icap +2jcap) ms-².the y coordinate of the particle in 2sec is.​

Answer 1

Hi !

ANSWER

Given:

The initial velocity of particle is u=10j^m/s

The acceleration of the particle is a=8i^+2j^

(a)

The position of the particle at any instant is given by:

s=ut+21at2

xi^+yj^=4t2i^+(10t+t2)j^

Comparing the X and Y component of the position:

x=4t2

x=16⟹t=2s

y=10t+t2

At t=2, y=24m

(b)

The speed of the particle at any instant is given by:

v=u+at

v=10j^+(8i^+2j^)2

v=14j^+16i^