Question

A partice of mass 1kg is acted upon by a force f= 4i+4j n which displaced it from a poing p(0,0)to q(1m,1m) .If initial speed of particle is 3m/s then its final speed is

Answer 1

Answer:

5m/s

Explanation:

Given, m=1kg, u=3m/s, then v=?

Now,

pq (s) = √1²+1² = √2m , f = √4²+4² = 4√2N

so,

f = ma = 4√2

1xa = 4√2, a = 4√2m/s²

use,

v² = u²+2as

v² = 3²+2x4√2x√2 = 9+16 = 25

v = √25 = 5m/s.