A particl is thrown up vertically with a speed v1 in air . it takes time t1 in upward journey and return t2(>t1) in the downward journey and return to the starting point with a speed v2.then
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V1 > V2
EXPLANATION:
If more time is taken, then the speed of the particle must be less.
Vice versa, if less time is taken, then the speed of the particle must be more.
In the question, its given t2>t1.
So therefore v1 will be greater than v2.
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