Question

A particle a is moving along a straight line with velocity 3m/s and another particle b has a velocity 5m/s at an angle 30°

Answer 1

Answer:

0.5 m/s^2 will be relative velocity.

Explanation:

If we take the velocity of the particle A to be = 3 m/s. And the particle B to be with velocity of 5 m/s. Since, the particle B is in 30 degree with the horizon along which particle A is moving. So, the component of the particle B in horizontal direction will be 5cos30.    

So, now velocity of the particle B will be = 5*cos30.

= 5 * 1/ 2 .

= 2.5 m/s.

Therefore, the relative velocity of B with respect to A will be given by the relation V(ba) = 3 - 2.5 which will be equal to 0.5 m/s.