Question

A particle A moving with a certain velocity has a de Broglie wavelength of 1A. If
particle B has mass 25% of that A and velocity 75% of that of A, the de Broglie
wavelength of B will be approximately ​

Answer 1

Answer:

5.33A°

Explanation:

ambda A=1A°=10^-10m

mB=25℅ of mA

mB=1/4×mA

vB=75/100×vA=3/4×vA

lambda A=h/mA.vA

mA.vA=h/10^-10m

lambda B=h/mB.vB

lambda B=h/(mA/4×3/4vA)

lambda B=(16/3)h/h×10^-10

lambda B=5.33×10^-10m

lambda B=5.33A°