A particle a moving with a certain velocity has a de broglie wavelength of 1 . if particle b has mass 25% of a and velocity 75% of a, the wavelength of b will be approximately:
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The wavelength of b will be approximately λB = 5.33 A°
Explanation:
Given data:
Mass of particle b = 25 % of a
Velocity of b = 75% of a
λA = 1°A
mA : mB = 4 : 1
We know that
λ = h / mv
vA : vB = 4 : 3
λB : λA = 16 : 3
λB = 5.33 A°
Thus the wavelength of b will be approximately λB = 5.33 A°
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