Question

A particle (a mud peller) of mass m strikes a smooth stationary wedge of mass M with velocity vo at an angle Owith horizontal. If th
collision is perfect inelastic collision then change in KE of the system (M+m) in the collision is
(M+msin20) mu^2/K(M+m)
then Kis
​

Answer 1

Answer:

Let the system (M+m) moves as a single mass with a velocity ν.

Conserving the momentum of the system in horizontal, we have mν

0

cosθ=(M+m)ν

This gives ν=

M+m

mν

0

cosθ

b) The change in KE of the system is

ΔK=

2

1

(M+m)ν

2

2

1

mν

0

2

where ν=

M+m

mν

0

cosθ

This gives ΔK=

2

(M+m)

(

M+m

mν

0

cosθ

)

2

−

2

1

mν

0

2

=−

2

mν

0

2

(1−

M+m

m

cos

2

θ)

=−

2(M+m)

(M+msin

2

θ)mν

0

2

Explanation:

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