Question

A particle accelerated from rest to 30 m/s in in 10 seconds distance travelled by a particle in next 10 seconds​

Answer 1

Answer ⇒ The distance traveled by the distance is 450 m

Explanation ⇒

Initial velocity, u = 0

Final velocity, v = 30 m/s.

time = 10 seconds.

Acceleration = 30/10

∴ a = 3 m/s².

Now, In nect 10 seconds,

Initial velocity, u = 30 m/s.

time = 10 seconds.

a = 3 m/s².

Thus,

Using the formula,

S = ut + 1/2 × at²

∴ S = 30 × 10 + 3 × 100/2

∴ S = 300 + 3 × 50

∴ S = 300 + 150

∴ S = 450 m.

Hence, the distance traveled by the distance is 450 m.

Hope it helps.

Answer 2

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