Question

A particle accelerates from a velocity of 10 m/s to 20 m/s over a distance of 5 m . The acceleration is

Answer 1

Answer:

initial velocity(u)= 10m/s

final velocity(v)= 20m/s

distance(s)= 5m

acceleration (a)=?

v² - u² = 2as

20²-10²=2(a)5

400-100=10a

300=10a

a=300/10

a=30m/s²

Answer 2

Given : -

A particle accelerates from a velocity of 10 m/s to 20 m/s over a distance of 5 meters .

Required to find : -

• Acceleration of the particle ?

Equation used : -

• v² - u² = 2as

Here,

v = Final velocity

u = Initial velocity

a = acceleration

s = displacement

Solution : -

A particle accelerates from a velocity of 10 m/s to 20 m/s over a distance of 5 meters .

we need to find the acceleration of the particle .

So,

From the given data we can conclude that ;

• Initial velocity of the particle ( u ) = 10 m/s

• Final velocity of the particle ( v ) = 20 m/s

• Displacement ( s ) = 5 meters

Now,

Let's find the acceleration of the particle.

So,

Using the equation of motion ;

i.e. v² - u² = 2as

=> ( 20 )² - ( 10 )² = 2 x a x 5

=> 400 - 100 = 2 x a x 5

=> 300 = 2 x a x 5

=> 300 = 10a

=> 10a = 300

=> a = 300/10

=> a = 30 m/s²

Hence,

• Acceleration ( a ) = 30 m/s²

Therefore ,

• Acceleration of the particle = 30 m/s²

Additional Information : -

The other equations of the motion are ;

• s = ut + ½ at²

• v = u + at

These equations of motion are only applicable when the acceleration of the body is constant .

Velocity is a vector quantity .

Speed is a scalar quantity .

Vector quantities needs both magnitude & direction .

Scalar quantities needs only magnitude but not direction .

The displacement can be taken in the terms of distance in some cases .

But,

we can't take distance in terms of displacement .

If initial velocity of the body is greater than the final velocity of the body it indicates that the acceleration is negative .

Negative Acceleration is called as Retardation .

The SI unit of acceleration is m/s² .

Instantaneous speed is the speed of the body at any instant .