Question

A particle accelerates uniformly from
rest at 6ms-1 for 8s and then decelerates
uniformly to rest in the next 5s.
Determine the speed
A. 9.6 ms-1
B. 48 ms-1
C. 30 ms-1
D. 24 ms-1​
Please show solving

Answer 1

$\fbox\orange{A}\fbox\pink{N}\fbox\blue{S}\fbox\red{W}\fbox\purple{E}\fbox\red{R}$

v = u + at

At rest, u = 0

v = at = 6 x 8 = 48

At stage 2, "V" from stage 1 becomes initial velocity "U" of stage 2

At rest v = 0

v = u + at

u = dt, deceleration is negative acceleration (d = -a)

d = u/t = 48/5 = 9.6 ms

Correct option is A

Answer 2

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