A particle accelerates uniformly with a rate 10 m/s2 and then starts decelerating with a rate of 5 m/s2, if the total time of journey is 10 s, then the maximum velocity attained by it, is
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A particle accelerates uniformly with a rate 10 m/s2 and then starts decelerating with a rate of 5 m/s2, if the total time of journey is 10 s, then the maximum velocity attained by it, is
Explanation:
The total distance travelled is = 625 m
The initial velocity is
u = 0 m s − 1
The acceleration is a = 10 m s − ²
The time is
t = 5 s
Apply the equation of motion
v = u + a t
The velocity is
v = 0 + 10 * 5 = 50 m s − ¹
The distance travelled in the first
5 s is
s = u t + 1/ 2 a t ²
= 0 ⋅ 5 + 1 /2 * 10 * 5 2 = 125 m
The distance travelled in the following
10 s is
s ₁ = v t 1 = 50 * 10
= 500 m
The total distance travelled is
d = s + s 1 = 125 + 500
= 625 m
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