A particle after starting from rest experiences constant acceleration for 20 second .If it covers a distance of S1 in the first 10 second and distance S2 in the 10 second then find out the relation between S1 and S2
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Answered by
1
the distance covered by the particle is same.....
S1 is equal to S2
Answered by
2
PROCEDURE
Using: s=u+at
We have,
u=0 m/s
a=constant
t=20 sec
S1:-
S1= 0 + a.10
S2:-
S2=0 + a.10
=> S1=S2
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