Question

A particle at a height'h'from the ground is projected with an angle 30° from the horizontal it strikes
the ground making angle 45° with horizontal. It is again projected from the same point at height h with
the same speed but with an angle of 60° with horizontal. Find the angle it makes with the horizontal
when it strikes the ground:​

Answer 1

Answer:

√5

Explanation:

Usingv=u2+2gh−−−−−−−√

v=u2sin2θ+2gh−−−−−−−−−−−−√

(vertical comp. When striking)

Now tan45∘=1

ucosθ=u2sin2θ=2gh−−−−−−−−−−−−√

u2cos2θ=u2sin2θ+2gh

u2(24−14)=2gh

u2=4gh⇒u=2gh−−√

tanθ=V⊥VH=4gh.34+2gh−−−−−−−−−−√2gh−−√×12=5gh−−−√gh−−√=5–√