Question

A particle at rest starts moving along a horizontal straight line with a uniform acceleration a0. The distance travelled in the 4th second of its motion is

Answer 1

Answer:

$\frac{a_{0} }{2}$ × 7

explanation:

$s_{t}$ = u + $\frac{a}{2} (2t-1)$ [formula to find the displacement travelled in nth second]

u = 0 (starts at rest)

t= 4s

a = a0

substituting the values you'll get the answer

Answer 2

u=0, a=a0, n=4

Sn = u+[n-½]*a

Sn = 0+[4-½]*a0

Sn = [8/2 - ½]*a0

Sn = 7/2*a0

So, Sn = 7a0/2