Question

A particle at rest starts moving along a horizontal straight line with a uniform acceleration a0. The distance travelled in the 4th second of its motion is

Answer 1

Answer:

After the 2nd second: (1/2)*a*(2s)^2

After the 3rd second: (1/2)* a*(3s)^2

In the third second: (1/2)* a*(3s)^2 - (1/2)* a*(2s)^2 = (1/2)* a*5 s^2

After the 3nd second: (1/2)*a*(3s)^2

After the 4rd second: (1/2)* a*(4s)^2

In the fourth second: (1/2)* a*(4s)^2 - (1/2)* a*(3s)^2 = (1/2)* a*7 s^2