Question

A particle attached to one end of a string whose other end is fixed, is
released from the position shown (when the string is horizontal). The
angle e when the tension in the string is equal to the weight of the
particle is?
​

Answer 1

Answer:

Given,

Tension in the string is equal to the weight of the body, T=mg

Kinetic energy = potential energy

21mv2=mg(rcosθ) …… (1)

Tension is the string, T=rmv2+mgcosθ

mg=r2(2mv2)+mgcosθ

from equation (1)

⇒mg=r2(mgrcosθ)+mgcosθ

⇒cosθ=31  

⇒θ=cos−1(31) 

Explanation:

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