a particle cover distance AB with radius r and makes an angle of 120 degree at the centre. find the displacement
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guptakrishna08162006:
how radius is 7
plz tell me
waiy
wait
In triangle ABO, ∠AOB=θ
AB is the displacement of the particle.
Using cosθ=
2(AO)(BO)
AO
2
+BO
2
−AB
2
Or cosθ=
2R
2
R
2
+R
2
−AB
2
We get AB
2
=2R
2
−2R
2
cosθ
Or AB
2
=2R
2
(1−cosθ)=2R
2
×2sin
2
(
2
θ
)
⟹ AB=2Rsin
2
θ
Distance covered by the particle d=Rθ
Thus ratio of distance and displacement
AB
d
=
2sin
2
θ
θ
please mark me as brainilest
AB is the displacement of the particle.
Using cosθ=
2(AO)(BO)
AO
2
+BO
2
−AB
2
Or cosθ=
2R
2
R
2
+R
2
−AB
2
We get AB
2
=2R
2
−2R
2
cosθ
Or AB
2
=2R
2
(1−cosθ)=2R
2
×2sin
2
(
2
θ
)
⟹ AB=2Rsin
2
θ
Distance covered by the particle d=Rθ
Thus ratio of distance and displacement
AB
d
=
2sin
2
θ
θ
please mark me as brainilest
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