A particle covers 10 m in first 5 sec and 10 m in next 3 sec . assuming constant acceleration,find the initial speed,acceleration and distance covered in next 2 sec.
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Intial velocity=10/5m/s=2m/s
final velocity=10/3m/s
acceleration=v-u/2=(2-10/3)m/s=-4/3.
distance covered in next 2second=10/3×2m=20/3m
final velocity=10/3m/s
acceleration=v-u/2=(2-10/3)m/s=-4/3.
distance covered in next 2second=10/3×2m=20/3m
Mausam11:
constant acceleration means there is no chage in velocity hence the velocity aftr 10s is same that is 15m/s.
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Answer:
20/3m
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