Question

A particle covers 10 metres in first 5 seconds and 10 metres in 3 seconds assuming constant acceleration find initial speed, acceleration and distance covered in next 2 seconds​

Answer 1

Answer:

Answer:

1. 8.3 m

Explanation:

Particle travels

10 m

in first

5

seconds

Using equation of motion

S = ut +

1

2

at

2

10

=

5u

+

25a

2

Multiply both sides with

8

80

=

40u + 100a

—

Answer 2

Answer:

(i)Let the initial velocity = uTotal distance= 20mTime taken= 8secS= ut+½ at²20=8u+32a20+8a=5..................(1)

(ii)For First 5seconds S=10m;t= 5secS= ut+½ at²10=u (5)+½a(5)²10=5u+25/2a20=10u+25a2u+5a=4....................(2)Solving equations (1) and (2)