Question

A particle covers 10 metres in first 5 seconds and 10 metres in next 3 seconds assuming constant acceleration find initial speed acceleration and distance covered in next two seconds​

Answer 1

Explanation:

using the equation of motion

s=ut+ 1/2at2

10=5u+ 1/2a(5)2

20=10u+25a

4=2u+5a_(1)

In next 3s the particle covers more 10m distance. So

20=8u+ 1/2a(8)2

5=2u+8a_(2)

solving equation (1) and (2)

4=2u+5a

5=2u+8a

a= 1/3m/s2

Put the value of a in equation (1)

u= 7/6 m/s

Now to find distance in next 10 s. total time will be 10s

s= 7/6×10+1/2×1/3×(10)2

s=28.33m

Distance travelled in next 2 sec

s=28.33−20=8.33m

Answer 2

Explanation:

see the attachment.

Hope it helps you