Question

A particle covers 10m in 1st 5sec and 10m in next 3sec. Assuming constant acceleration. Find the initial speed, acceleration and distance covered in next 2sec

Answer 1

So,

Given time = 5 sec

Distance = 10 m
So, speed = 2m/s

and again time = 8 sec

Distance = 20 m

So, speed = 20/8 m/s

Using v = u + at
 
20/7 = 2 + 8a
a = 6/ 64 m/s²

So int time 10 sec it will cover distance 

s = ut +1/2at²
s = 28.125 m

So, 

Distance covered in next 2 sec
28.125 m - 20 m  = 8 m (approx)