Question

A particle covers 10m to first 5s and 10m in next 3s.

Assuring constant acceleration. Find initial speed acceleration

and distance covered in neat 2s.?​

Answer 1

So given time = 5 sec

distance = 10 m

so speed = 2m/s

and again

time = 8 sec

distance = 20 m

so speed = 20/8 m/s

so using v = u + at

20/7 = 2 + 8a

a = 6/ 64 m/s²

so int time 10 sec it will cover distance

s = ut +1/2at²

s = 28.125 m

so distance covered in next 2 sec

28.125 m - 20 m = 8 m (approx)