Question

A particle covers 150 m in 8th second starting from rest it's accerlation is​

Answer 1

Given :

Distance covered by the particle = 150m.

Initial velocity, u = zero.

Particular time, n = 8

To find :

The accerlation of the particle.

Solution :

Acceleration is measured as the rate of change of velocity.

It is a vector quantity having both magnitude and direction

using equation of motion .i.e.,

• s = u + 1/2a(2n - 1)

here,

s denotes distance

u denotes initial velocity

n denotes particular second.

substituting all the given values,

${ \leadsto{ \sf{s = u + \dfrac{1}{2} a(2n - 1)}}}$

${ \leadsto{ \sf{150 = 0 + \dfrac{1}{2} a(2 \times 8 - 1)}}}$

${ \leadsto{ \sf{150 = \dfrac{1}{2} a(15)}}}$

${ \leadsto{ \sf{ \dfrac{150}{15} = \dfrac{1}{2} a}}}$

${ \leadsto{ \sf{10 \times 2 = a}}}$

${ \leadsto{ \sf{ a = 20 {ms}^{ - 2} }}}$

thus, the accerlation of the particle is 20m/s².

Remember !

SI unit of accerlation is m/s²