Question

A particle covers 50 m distance when projected with an initial speed. On the same surface it will
cover a distance, when projected with double the initial speed (RPMT 2000)​

Answer 1

Answer:

In projectile motion,

Range, R=gu2sin2θ=50m  (Given)

Now, Initial speed is u′=2u

R′=g4u2sin2θ=4×50

R′=200m

The correct option is C.

Explanation:

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